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2votes
1answer
90views

Analytic approximation of bound state energies for finite square well

Considering a fairly deep finite potential well given by: $$U(x)= \begin{cases} U_0 \ \ , \ \ |x|>\frac{a}{2}\\ 0 \ \ , \ \ |x|\le \frac{a}{2} \end{cases}$$ We know that the energies of the bound ...
Krum Kutsarov's user avatar
1vote
1answer
124views

Can the non-degenerate perturbation theory formula for higher-order energy corrections be used in case of degenerate perturbation theory?

Consider the system given by, $$ H|n\rangle = E|n\rangle$$ where: $H$ is the hamiltonian. $|n\rangle$ is the eigenstate. $E$ is the energy of the eigenstate. Now from $\underline{\textbf{non-...
user544899's user avatar
0votes
1answer
115views

Graphical representations of the vector model of quantum angular momentum

This question is in reference to the book "Introduction to Modern Physics" by Richtmyer and Kennard, particularly in their discussion of the graphical representation of quantized angular ...
QuantumExplorer's user avatar
1vote
2answers
111views

Trouble understing a passage from Principles of quantum mechanics by Paul Dirac?

I'm currently reading Principles of Quantum Mechanics by Paul Dirac, specifically the 4th edition of 1958. There is a passage I'm having trouble to understand, I'll put the text here. For reference it'...
user424762's user avatar
2votes
2answers
225views

The eigenvectors associated to the continuous spectrum in Dirac formalism

I am comfused about the definition of an observable, eigenvectors and the spectrum in the physics litterature. All what I did understand from Dirac's monograph is that the state space is a complex ...
user536450's user avatar
0votes
1answer
63views

Pauli matrix exponentials [closed]

Just a short query to confirm my understanding. Given the Pauli-X operator $\hat{X}$ and it's eigenstates $|+\rangle:=\frac{1}{\sqrt{2}}(|0\rangle + |1\rangle)$ and $|-\rangle:=\frac{1}{\sqrt{2}}(|0\...
John Doe's user avatar
0votes
1answer
97views

What kind of physical process would correspond to an operator that doesn’t result in an eigenvalue equation: $ \hat{A}ψ=a ψ$?

I'm studying quantum mechanics and I'm trying to understand the concept of operators. They can be represented in general by the equation: $$ \hat{A}ψ=ψ'. $$ Here the wavefunction is changed to $ψ'$ ...
bananenheld's user avatar
2votes
2answers
739views

Change of basis in bra-ket notation [duplicate]

In the post Change of Basis in quantum mechanics using Bra-Ket notation , the accepted answer explores the relationship between an arbitrary operator $\hat{x}$ and another named $\hat{u}$, such that $\...
JBatswani's user avatar
0votes
1answer
105views

TISE solutions should be combinations of eigenstates. Why this is not the case? [closed]

I would really appreciate some help with a question I have about the TISE (Sch. tipe independent equation). This is a linear equation and linear combination of the solution should be solution too. The ...
Domenico Giardino's user avatar
0votes
1answer
129views

An operator with integer eigenvalues?

As is well-known, number operator $N=a^{\dagger}a$ with the commutation relation $[a,a^{\dagger}]=1$ has non-negative integer eigenvalues. I am looking for a similar expression for an operator ($A(a^{\...
Arian's user avatar
0votes
1answer
145views

Commutable operators and eigenfunctions

My lecture notes says Since $[\hat{L^2} ,\hat{L_{z}}] = 0$ Then $Y(\theta,\phi)$ solves the below equations simultaneously: $$\hat{L^2}Y(\theta,\phi) = A Y(\theta,\phi)$$ $$\hat{L_{z}}Y(\theta,\phi) = ...
jensen paull's user avatar
0votes
3answers
188views

Why does $Z \otimes Z$ have only two eigenvalues?

The observable $Z = \begin{bmatrix}1 & 0\\\ 0 & -1\end{bmatrix}$ on a single qubit system has two eigenvalues, 1 and -1, which means when measured, the system can give one of two possible ...
Neeraj's user avatar
1vote
3answers
3kviews

Physical interpretation of the bra-ket notation

The bra-ket notation generally consists of 'ket', i.e. a vector, and a 'bra', i.e. some linear map that maps a vector to a number in the complex plane. Now, using this bra-ket notation we can compute ...
Rasmus Andersen's user avatar
4votes
2answers
896views

Calculating eigenvalues and eigenstates of an infinite dimensional Hamiltonian

Consider the Hamiltonian, $$H = E_{0} \sum_{m = - \infty}^{\infty}(|m⟩⟨m + 1| + h.c.),$$ where $E_{0}$ is an energy scale, $|m⟩$ are kets which can be used to form a complete basis and h.c. denotes ...
ShKol's user avatar
1vote
0answers
91views

Green Function associated to a periodic Schrodinger operator

If $V:\mathbb R\to \mathbb R$ is an $L$ periodic function in $\operatorname L^{\infty}$ we can always find two independent solutions for $$\psi''(x)+V(x)\psi(x)=E\psi(x)$$ $\psi^{\pm}(x)=e^{\pm ipx}\...
Vajra's user avatar

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